A tennis player can serve the ball of mas 57g at an initial horizontal speed of 55ms^-1 the ball remains in contact with the racket for 0.055s. Calculate the average force exerted on the ball during the serve.
force*time=mass*changeinVelocity
it would be 57000
To calculate the average force exerted on the ball during the serve, we can use Newton's second law of motion, which states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a).
1. First, let's calculate the acceleration of the ball during the serve. We can use the equation a = Δv / Δt, where Δv is the change in velocity and Δt is the change in time.
The initial horizontal speed of the ball is 55 m/s. Since the ball remains in contact with the racket for 0.055 seconds, the change in velocity is the final velocity (0 m/s) minus the initial velocity (55 m/s).
Δv = 0 - 55 = -55 m/s (the negative sign indicates a decrease in velocity)
Δt = 0.055 s
a = -55 m/s / 0.055 s = -1000 m/s²
2. Next, we can calculate the force exerted on the ball by multiplying the mass of the ball by its acceleration.
m = 57 g = 57/1000 kg = 0.057 kg
F = m * a = 0.057 kg * -1000 m/s²
F = -57 N
Therefore, the average force exerted on the ball during the serve is approximately 57 Newtons, with the negative sign indicating that the force is directed opposite to the initial movement of the ball.