The perimeter of a rectangle is 90 cm. Its width is half its length. Which equation could be solved to find the dimensions of the rectangle?
if width is 1/2 the length, then length is twice the width, so
width --- x
length ---2x
2(x) + 2(2x) = 90
there is your equation, the x would be the width as I defined it as such.
To find the dimensions of the rectangle, we need to set up an equation using the given information.
Let's assume that the length of the rectangle is "L" cm. According to the given information, the width is half the length. Therefore, the width of the rectangle would be "L/2" cm.
The formula for the perimeter of a rectangle is P = 2(L + W), where P is the perimeter, L is the length, and W is the width.
In this case, the perimeter is given as 90 cm. So we can substitute the values into the formula:
90 = 2(L + L/2)
Now, let's simplify the equation:
90 = 2(3/2)L
= (3/2)2L
= 3L
Now we have the equation 3L = 90.
To find the length of the rectangle, we need to solve this equation for L.
Dividing both sides of the equation by 3:
3L / 3 = 90 / 3
L = 30
Therefore, the length of the rectangle is 30 cm.
Since the width is half the length, the width would be:
W = L/2 = 30/2 = 15 cm
So, the dimensions of the rectangle are length = 30 cm and width = 15 cm.
Therefore, the equation that could be solved to find the dimensions of the rectangle is 3L = 90.