What is the molar concentration of a solution of sulfuric acid, H2SO4, if 4.64 mL react completely with 0.644 g of NaOH which was dissolved in 200 mL of water?
Hint given in feedback
2NaOH + H2SO4 ==> 2H2O + Na2SO4
mols NaOH = grams/molar mass = 0.644/40 = approx 0.016 but you need a better answer than this estimate.
mols H2SO4 = 1/2 mols NaOH (Look at the coefficients in the equation)= 0.008.
M H2SO4 = mols/L. You know mols and you know L, solve for M.
The point of this problem is that is doesn't matter a whit how much water you had in the NaOH, it's the mols NaOH that count and that is determined by the grams.
Well, if you give me a hint, I'll give you a funny interpretation! So, here's the hint: "Molar concentration is calculated by dividing the number of moles of solute by the volume of the solution in liters."
Alright, let's get started. First, we need to find the number of moles of NaOH. We can use its molar mass, which is approximately 40 g/mol. Dividing 0.644 g by 40 g/mol, we get around 0.0161 moles of NaOH.
Now, let's convert the volume of water from milliliters to liters. Since there are 1000 mL in a liter, 200 mL is equal to 0.2 liters.
Finally, we can calculate the molar concentration. We divide the number of moles of NaOH by the volume of the solution in liters. That gives us 0.0161 moles divided by 0.2 liters, which equals approximately 0.0805 M.
So, the molar concentration of the sulfuric acid solution is around 0.0805 M. Now that wasn't too acidic, was it? It's just a mildly concentrated solution, not enough to make you squirm like a lemon!
To determine the molar concentration of the sulfuric acid (H2SO4) solution, we need to use the given information and the balanced chemical equation for the reaction between sulfuric acid and sodium hydroxide (NaOH).
Step 1: Write the balanced chemical equation.
H2SO4 + 2NaOH -> 2H2O + Na2SO4
Step 2: Calculate the number of moles of NaOH.
Given mass of NaOH = 0.644 g
Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.99 g/mol
Number of moles of NaOH = Mass / Molar mass = 0.644 g / 39.99 g/mol ≈ 0.0161 mol
Step 3: Determine the stoichiometry of the reaction.
From the balanced chemical equation, we can see that 1 mole of sulfuric acid (H2SO4) reacts with 2 moles of sodium hydroxide (NaOH).
Step 4: Calculate the number of moles of sulfuric acid (H2SO4).
Since the reaction is 1:2, the number of moles of sulfuric acid (H2SO4) is half of the number of moles of NaOH.
Number of moles of H2SO4 = 0.0161 mol / 2 ≈ 0.00805 mol
Step 5: Calculate the molar concentration.
Molar concentration (Molarity) is defined as moles of solute divided by the volume of solution in liters.
Given volume of solution = 200 mL = 0.2 L
Molar concentration of H2SO4 = Number of moles of H2SO4 / Volume of solution
Molar concentration of H2SO4 = 0.00805 mol / 0.2 L = 0.04025 mol/L
Therefore, the molar concentration of the sulfuric acid (H2SO4) solution is approximately 0.04025 mol/L.
To find the molar concentration of sulfuric acid (H2SO4), we need to first calculate the number of moles of NaOH that reacted with the acid.
Step 1: Calculate the moles of NaOH
We are given the mass of NaOH (0.644 g) and the molar mass of NaOH (40.00 g/mol).
Using the formula:
moles = mass / molar mass, we can calculate the moles of NaOH as follows:
moles of NaOH = 0.644 g / 40.00 g/mol
Step 2: Calculate the moles of H2SO4
From the balanced equation:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O,
we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH.
So the moles of H2SO4 will be half of the moles of NaOH.
moles of H2SO4 = (moles of NaOH) / 2
Step 3: Calculate the volume of the solution
We are given the initial volume of water, which is 200 mL. This volume does not change when the sulfuric acid reacts with NaOH.
Step 4: Calculate the molar concentration
The molar concentration (Molarity) is defined as moles of solute per liter of solution.
Since the volume of the solution is given in mL, we need to convert it to liters by dividing by 1000.
Molarity = (moles of H2SO4) / (volume of solution in liters)
Now, let's calculate the molar concentration of the sulfuric acid solution.
Moles of NaOH = 0.644 g / 40.00 g/mol = 0.0161 mol
Moles of H2SO4 = 0.0161 mol / 2 = 0.00805 mol
Volume of solution = 200 mL / 1000 = 0.2 L
Molarity = 0.00805 mol / 0.2 L = 0.04025 mol/L
Therefore, the molar concentration of the solution of sulfuric acid (H2SO4) is 0.04025 mol/L.