Mass (g) of solute in 179.8 mL of 0.267 M calcium acetate
Well, well, well, look who's got some chemistry on their plate! Okay, let's calculate the mass of solute, but I promise to keep it fun and entertaining.
To start, we need to use the formula C = n/V, where C is the concentration, n is the number of moles of solute, and V is the volume in liters. So, let's convert the volume from milliliters to liters:
179.8 mL = 0.1798 L
Now, we can plug in the given values into the equation:
0.267 M = n/0.1798 L
Alright, let's solve for n (moles of solute):
n = 0.267 M x 0.1798 L
You ready for the punchline? *Drumroll please.* The number of moles of solute is approximately 0.0479 moles.
But wait, we're not done yet! We still need to calculate the mass of the solute. Luckily, we can use the molar mass to do that. The molar mass of calcium acetate (Ca(C2H3O2)2) is approximately 158.17 g/mol.
Now let's multiply the number of moles by the molar mass to find the mass of solute:
Mass = 0.0479 mol x 158.17 g/mol
And the hilarious answer is... approximately 7.57 grams.
Ta-da! There you have it. Hope that satisfied your chemistry craving while giving you a chuckle or two.
To find the mass of the solute in a given volume and concentration, you can use the formula:
Mass (g) = Volume (L) x Concentration (M) x Molar Mass (g/mol)
First, convert the volume from milliliters (mL) to liters (L):
179.8 mL = 179.8/1000 L = 0.1798 L
Next, multiply the volume (in liters) by the concentration (in moles per liter) to find the number of moles of solute:
Number of moles = Volume (L) x Concentration (M)
= 0.1798 L x 0.267 M
= 0.048
Lastly, multiply the number of moles by the molar mass of calcium acetate to find the mass of the solute:
Molar mass of calcium acetate (Ca(CH3COO)2) = atomic mass of calcium (Ca) + 2 x atomic mass of carbon (C) + 6 x atomic mass of hydrogen (H) + 4 x atomic mass of oxygen (O)
Using the atomic masses from the periodic table:
Molar mass of calcium acetate (Ca(CH3COO)2) = 40.08 + 2 x 12.01 + 6 x 1.01 + 4 x 16.00
= 158.17 g/mol
Mass (g) = Number of moles x Molar mass
= 0.048 mol x 158.17 g/mol
= 7.58 g
Therefore, the mass of the solute in 179.8 mL of 0.267 M calcium acetate is 7.58 grams.
To find the mass of solute in a given volume of a solution, you'll need to know the molarity of the solution and the volume of the solution. In this case, you're given the volume of the solution (179.8 mL) and the molarity of the solution (0.267 M).
The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. This means that a 0.267 M solution of calcium acetate contains 0.267 moles of calcium acetate per liter of solution.
Step 1: Convert the given volume to liters.
179.8 mL = 179.8/1000 = 0.1798 L
Step 2: Use the molarity and volume to calculate the number of moles of calcium acetate in the solution.
moles of calcium acetate = molarity × volume (in liters)
moles of calcium acetate = 0.267 M × 0.1798 L
Step 3: Calculate the mass of calcium acetate using the molar mass of calcium acetate.
The molar mass of calcium acetate (Ca(CH3COO)2) can be found by adding up the atomic masses of each element in the chemical formula:
(1 × atomic mass of Ca) + (2 × atomic mass of C) + (6 × atomic mass of H) + (4 × atomic mass of O)
Once you have the molar mass, you can use it to convert moles to grams:
mass (g) = moles × molar mass
Step 4: Look up the atomic masses of each element and calculate the molar mass of calcium acetate:
Atomic mass of Ca = 40.08 g/mol
Atomic mass of C = 12.01 g/mol
Atomic mass of H = 1.01 g/mol
Atomic mass of O = 16.00 g/mol
Molar mass of Ca(CH3COO)2 = (40.08 g/mol) + (2 × 12.01 g/mol) + (6 × 1.01 g/mol) + (4 × 16.00 g/mol)
Step 5: Plug in the values into the equation to calculate the mass of solute:
mass (g) = moles × molar mass
mass (g) = (0.267 mol/L × 0.1798 L) × molar mass
Now, you have all the values to substitute into the equation to calculate the mass of solute. Calculate it using the given values.
mols = M x L = ?
Then g = mols x molar mass