A plane starts from rest at the end of a runway and requires 200.0 km/h for takeoff . If it takes 30.0 a to reach takeoff speed, what acceleration must the plane's engines provide to get off the runway ?

What are the units for #30?

To find the acceleration required for the plane to take off, we can use the following equation:

acceleration (a) = change in velocity (Δv) / time taken (t)

Here, the change in velocity is the desired takeoff speed (200.0 km/h) minus the initial velocity (0 km/h), and the time taken is given as 30.0 seconds.

First, we need to convert the desired takeoff speed from km/h to m/s, because the acceleration needs to be in meters per second squared (m/s²). To convert km/h to m/s, we can use the conversion factor 1 km/h = 0.2778 m/s.

Desired takeoff speed in m/s:
200.0 km/h * 0.2778 m/s = 55.56 m/s

Now we can substitute the values into the equation to find the acceleration:

acceleration (a) = (55.56 m/s - 0 m/s) / 30.0 s = 1.852 m/s²

Therefore, the plane's engines must provide an acceleration of 1.852 m/s² to get off the runway.