a locomotive is accelerating at 1.6 meters per second it passes through a 20.1 meter wide crossing in a time of 4.03 seconds after the locomotive leaves the crossing how much time is required until it's speed reaches 5.3 meters per second
Well, aren't locomotives just train-ing to impress us with their speed? Let's chug along and calculate the time it takes for the locomotive to reach a speed of 5.3 meters per second after leaving the crossing.
Since we know the initial speed, final speed, and acceleration, we can use the equation of motion: final speed equals initial speed plus acceleration times time.
So, 5.3 meters per second equals 1.6 meters per second plus acceleration times time. Solving for time, we get:
Time = (5.3 meters per second - 1.6 meters per second) / acceleration
Substituting in the given values, we have:
Time = (5.3 m/s - 1.6 m/s) / 1.6 m/s²
Calculating that out, we find:
Time = 2.56 seconds.
Therefore, it will take approximately 2.56 seconds for the locomotive's speed to reach 5.3 meters per second after leaving the crossing. So, if you blink, you might miss it!
To find the time required until the locomotive's speed reaches 5.3 meters per second, we need to use the equation for acceleration:
v = u + at
Where:
v = final velocity (5.3 m/s)
u = initial velocity (1.6 m/s)
a = acceleration (unknown)
t = time (unknown)
First, we need to find the acceleration (a). Rearranging the formula, we have:
a = (v - u) / t
Plugging in the given values, we get:
a = (5.3 m/s - 1.6 m/s) / t
a = 3.7 m/s / t
Now, let's calculate the time (t). Rearranging the formula, we have:
t = (v - u) / a
Plugging in the given values, we get:
t = (5.3 m/s - 1.6 m/s) / 3.7 m/s
t = 3.7 s
Therefore, it would take approximately 3.7 seconds for the locomotive's speed to reach 5.3 meters per second after it leaves the crossing.
To find out how much time is required until the locomotive's speed reaches 5.3 meters per second after it leaves the crossing, we need to use the equation of motion:
v = u + at
where
v = final velocity (5.3 meters per second)
u = initial velocity (0, as the locomotive starts from rest after leaving the crossing)
a = acceleration (1.6 meters per second squared)
t = time taken to reach the final velocity
We can rearrange the equation to solve for time (t):
t = (v - u) / a
Plugging in the given values, we have:
t = (5.3 - 0) / 1.6
t = 5.3 / 1.6
t ≈ 3.3125 seconds
Therefore, it would take approximately 3.3125 seconds for the locomotive's speed to reach 5.3 meters per second after it leaves the crossing.
initial velocity=distance/4.03 assumeing the locomaotive length is zero. Length of the locomotive is not given, think about that.
use the initial velocity above, with a very short locomotive.
Vf=vi+at
solve for time t.