A 2.00 gram sample of Copper (II) acetate produced 2.48 grams of a Copper (II) Formate Hydrate. After heating the sample the final mass of the Copper (II) Formate was 1.69 grams. What was the degree of hydration for the Copper (II) Formate?

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To determine the degree of hydration for Copper (II) Formate, we need to compare the mass of the water lost during heating to the mass of the anhydrous compound.

First, let's calculate the mass of water lost during heating:
Mass of Copper (II) Formate before heating = 2.48 grams
Mass of Copper (II) Formate after heating = 1.69 grams

Water lost during heating = Mass before heating - Mass after heating
Water lost during heating = 2.48 g - 1.69 g = 0.79 grams

Next, we need to calculate the mass of the anhydrous compound by subtracting the mass of water lost from the final mass of the Copper (II) Formate:
Mass of the anhydrous Copper (II) Formate = Mass after heating - Mass of water lost
Mass of the anhydrous Copper (II) Formate = 1.69 g - 0.79 g = 0.90 grams

Finally, we can calculate the degree of hydration using the following formula:
Degree of hydration = (Mass of water lost / Mass of anhydrous compound) × 100

Degree of hydration = (0.79 g / 0.90 g) × 100
Degree of hydration = 87.78%

Therefore, the degree of hydration for the Copper (II) Formate is approximately 87.78%.