Consider the unbalanced chemical reaction Al + Cl2 → AlCl3. How many moles of AlCl3 can be obtained from 360 grams of Cl2? (Molar masses: Cl = 35.45 g/mol, Al = 26.98 g/mol)
when i balance the equation i get 2Al+3Cl2->2AlCl3 but when i try to figure out the answer i keep getting the wrong answer. 360*1/70.90*1/53.96*2/3 = .0627 mol AlCl3
What's the 1/53.96 term?
The equation is balanced.
mols Cl2 = 360/70.9 = ?
mols AlCl3 = ?mols Cl2 x (2/3) = ?
I think the 1/53.96, whatever that is, is the problem.
To find the number of moles of AlCl3 obtained from 360 grams of Cl2, we need to use the molar masses of Cl2 and AlCl3.
The molar mass of Cl2 is 2 x 35.45 g/mol = 70.90 g/mol.
The molar mass of AlCl3 is (26.98 g/mol + 3 x 35.45 g/mol) = 133.33 g/mol.
Now, we can calculate the number of moles of AlCl3:
Number of moles of AlCl3 = (mass of Cl2 / molar mass of Cl2) x (molar ratio of AlCl3 / molar ratio of Cl2)
= (360 g / 70.90 g/mol) x (2 mol AlCl3 / 3 mol Cl2)
= 5.07 mol AlCl3.
Therefore, 360 grams of Cl2 can produce approximately 5.07 moles of AlCl3.
To find the number of moles of AlCl3 obtained from 360 grams of Cl2, we first need to balance the chemical equation correctly. The balanced equation is 2 Al + 3 Cl2 -> 2 AlCl3.
Now, let's calculate the molar mass of Cl2:
Molar mass of Cl2 = 2(35.45 g/mol) = 70.90 g/mol
Next, we can calculate the number of moles of Cl2 using the given mass and molar mass:
Number of moles of Cl2 = Mass (g) / Molar mass (g/mol) = 360 g / 70.90 g/mol = 5.07 mol Cl2
In the balanced equation, it shows that 3 moles of Cl2 react to form 2 moles of AlCl3. Therefore, we can use the ratio of the coefficients in the balanced equation to determine the moles of AlCl3 produced:
Number of moles of AlCl3 = (Number of moles of Cl2) x (2 moles of AlCl3 / 3 moles of Cl2)
= 5.07 mol Cl2 x (2 mol AlCl3 / 3 mol Cl2)
= 3.38 mol AlCl3
So, the correct answer is that 3.38 moles of AlCl3 can be obtained from 360 grams of Cl2.