A solar cell with dimensions 12cm x 12cm is illuminated at standard test conditions. The cell presents the following external parameters:
Voc=0.8V,Isc=3A,Vmp=0.75V,Imp=2.5A
Calculate the fill factor in percentage [%]:
Calculate the efficiency (in %):
0.22
To calculate the fill factor and efficiency of a solar cell, we need to understand the basic parameters involved.
1. Fill Factor (FF):
The fill factor is a measure of how well a solar cell converts light into electricity. It is defined as the ratio of the maximum power output from the solar cell (Vmp × Imp) to the product of the open-circuit voltage (Voc) and short-circuit current (Isc).
The formula for calculating the fill factor is as follows:
FF = (Vmp × Imp) / (Voc × Isc) * 100
2. Efficiency (η):
The efficiency of a solar cell is a measure of how much of the available energy from sunlight is converted into usable electrical energy. It is calculated as the ratio of the maximum power output (Pmax) to the incident power (Pin) from the sunlight.
The formula for calculating the efficiency is as follows:
η = (Pmax / Pin) * 100
In our case, the given parameters are as follows:
Voc = 0.8V
Isc = 3A
Vmp = 0.75V
Imp = 2.5A
Now, let's calculate the fill factor and efficiency.
Step 1: Calculate Fill Factor (FF)
FF = (Vmp × Imp) / (Voc × Isc) * 100
= (0.75V × 2.5A) / (0.8V × 3A) * 100
= 1.875W / 2.4W * 100
≈ 78.12%
So, the fill factor is approximately 78.12%.
Step 2: Calculate Efficiency (η)
To calculate efficiency, we need to know the incident power (Pin) from the sunlight, which is not provided in the given information. Without this information, we cannot calculate the efficiency accurately.
Please note that Pin represents the power of sunlight incident on the solar cell, and it depends on factors like solar radiation, temperature, and orientation. You would need additional information or measurements to calculate the efficiency accurately.
Hence, we cannot calculate the efficiency without the incident power (Pin) value.