Write the solution set of the inequality |x + 2| < 5 in the interval notation.

|x+2| < 5

x+2 < 5 AND -x-2 < 5
x < 3 AND x > -7

I always taught this notation:
-7 < x < 3

I will let you convert to your notation

(x+2) < 5 and -(x+2) <5

x < 3 and (x+2) > -5

x < 3 and x > -7
which is
-7 < x < 3

(-7,3) I think

I do not do interval notation either.

Interval notation: (-7,3)

If it was included (less than or equal to/greater than or equal to) you would use a bracket [ or ].

Yes.

To find the solution set of the inequality |x + 2| < 5, we can break it down into two separate inequalities:

1) x + 2 < 5
2) -(x + 2) < 5

For the first inequality, subtract 2 from both sides:
x < 3

For the second inequality, multiply both sides by -1, which changes the direction of the inequality sign:
x + 2 > -5
x > -7

Now, we can express the solution set using interval notation.

The solution set for the inequality |x + 2| < 5 is (-7, 3).