83 3rd graders 115 4th graders 150th graders all the 5th graders will be on one side and all the 4th graders will be on the other side the 3rd graders will be split up so that the two sides will have equal number of student how many 4th graders ?how many 3rd graders will be with the 5th graders?what will be the total number of students on each team?

Is that 150 fifth graders?

To solve this problem, we need to find the number of 4th graders and the number of 3rd graders that will be with the 5th graders. We also need to find the total number of students on each team.

Let's start by finding the number of 4th graders. We are given that there are 115 4th graders in total.

Since we want both sides to have an equal number of students, we can divide the total number of students by 2. So, we divide 115 by 2:

115 / 2 = 57.5

Since we can't have a fraction of a student, we round this answer to the nearest whole number. In this case, it would be 58.

So, there will be 58 4th graders on one side.

Next, let's find the number of 3rd graders that will be with the 5th graders. We are given that there are 83 3rd graders in total.

To split the 3rd graders equally, we divide the total number of 3rd graders by 2:

83 / 2 = 41.5

Rounding this answer to the nearest whole number, we get 42.

Therefore, there will be 42 3rd graders with the 5th graders.

Finally, let's find the total number of students on each team.

On one side, there will be 58 4th graders and 42 3rd graders with the 5th graders. So, the total number of students on that side is:

58 + 42 = 100

On the other side, there will be the remaining 83 - 42 = 41 3rd graders.

So, the total number of students on the other side is:

115 4th graders + 41 3rd graders = 156

Therefore, the total number of students on each team is 100 for the side with the 5th graders and 156 for the side with the 4th graders.