A renegade watermelon starts at x = 0 m and rolls at a constant velocity to x = −3.0 m at time t = 5.0 seconds. Then, it bumps into a wall and stops. Draw its position versus time graph from t = 0 s to t = 10 s.

Bounced on my boy's e=mc^2 to this for hours. My gentlelady, this question is the least of your concerns in this world we live in. There are people, like Martin Skrelli, and Mark Dice, who both blocked me on twitter. This question reminds me of the ever looming doom that the world is going to come to, because of the giant renegade watermelon hurdling towards us. And submit!

To draw the position versus time graph for the renegade watermelon, we can follow these steps:

1. Start by plotting the initial position of the watermelon. In this case, the initial position is x = 0 m. Mark this as the starting point of the graph.

2. Next, we need to find the velocity of the watermelon. We know that it rolls at a constant velocity from x = 0 m to x = -3.0 m in 5.0 seconds. To find the velocity, we can use the formula:

velocity = (final position - initial position) / time taken

velocity = (-3.0 m - 0 m) / 5.0 s
= -0.6 m/s

Therefore, the velocity of the watermelon is -0.6 m/s.

3. Now, we can apply this velocity to the rest of the graph. Since the watermelon bumps into a wall and stops at x = -3.0 m, we can assume that its velocity becomes zero after 5.0 seconds.

4. To draw the graph, we can plot the points for the first 5 seconds using the calculated velocity. The graph will show a linear decrease in the position from x = 0 m to x = -3.0 m, indicating the movement of the watermelon.

- At t = 0 seconds, the position is x = 0 m.
- At t = 5 seconds, the position is x = -3.0 m.

5. Finally, after 5.0 seconds, the position remains constant at x = -3.0 m since the watermelon has stopped rolling. We can extend this position on the graph in a horizontal line until t = 10 seconds.

The resulting position versus time graph will be a straight line with a negative slope from t = 0 s to t = 5 s showing the movement of the watermelon and a constant position of x = -3.0 m from t = 5 s to t = 10 s indicating that the watermelon has stopped.

I hope this helps! Let me know if you have any further questions.