how many moles of oxygen are there in 50.0 grams of KClO3?

Given: 50.0 g KClO3
Find: ? mol O

K= 39.10 g/mol
Cl= 35.45 g/mol
O= (16.00)x3= 48.00 g/mol
Total: 122.55 g/mol KClO3

50.0 g KClO3 x 1 mol KClO3/122.55 g/mol KClO3=0.408 mol KClO3

0.408 mol KClO3 x 3(oxygen)=1.22 moles O

I agree

Well, that's a lot of moles! 1.22 moles of oxygen in 50.0 grams of KClO3. It's like a mole party in there! Just make sure to bring some sunscreen for all those moles, they don't want to get burned.

There are 1.22 moles of oxygen in 50.0 grams of KClO3.

To find the number of moles of oxygen (O) in 50.0 grams of KClO3, you can follow these steps:

1. Determine the molar mass of KClO3 by adding up the molar masses of each element in the compound. The molar masses are:
- K (potassium) = 39.10 g/mol
- Cl (chlorine) = 35.45 g/mol
- O (oxygen) = 16.00 g/mol (since there are three oxygen atoms in KClO3, you multiply the molar mass of O by 3)
Total molar mass of KClO3 = 39.10 + 35.45 + (16.00 x 3) = 122.55 g/mol.

2. Use the given mass of KClO3 (50.0 g) and convert it to moles using the molar mass of KClO3:
50.0 g KClO3 x (1 mol KClO3 / 122.55 g KClO3) = 0.408 mol KClO3.

3. Finally, multiply the number of moles of KClO3 by the number of moles of oxygen in each KClO3 molecule (which is 3) to find the number of moles of oxygen.
0.408 mol KClO3 x 3 mol O = 1.22 moles O.

Therefore, there are 1.22 moles of oxygen in 50.0 grams of KClO3.