A robot probe drops a camera off the rim of a 429 m high cliff on Mars, where the free-fall acceleration is 3.7 m/s2.
What equation will be appropriate to find velocity?
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To find the velocity of the camera as it falls off the cliff on Mars, we can use the equation for free-fall motion:
v^2 = u^2 + 2as
Where:
v = final velocity (which is what we want to find)
u = initial velocity (which is 0, as the camera is dropped)
a = acceleration due to gravity (given as 3.7 m/s^2)
s = displacement (vertical distance fallen, given as 429 m)
Substituting the values into the equation, we get:
v^2 = 0 + 2 * 3.7 * 429
Simplifying further gives:
v^2 = 0 + 2515.4
Now we can solve for v by taking the square root of both sides:
v = √2515.4
So, the appropriate equation to find the velocity of the camera is v = √2515.4. By evaluating this equation, you will get the velocity of the camera as it falls off the cliff.