Bones are mostly calcium phosphate. Calcium chloride reacts with potassium phosphate to form calcium phosphate and potassium chloride. Indicate the physical states or reactants and products

a) Write the balanced equation of the information above

b) Determine the total ionic equation

3CaCl2(aq) + 2K3PO4(aq) ==> Ca3(PO4)2(s) + 6KCl(aq)

You add the phases.
3Ca^2+ + 6Cl^- + 6K^+ + 2PO4^3- ==> Ca3(PO4)2(s) + 6K^+ + 6Cl^-

You turn that into a net ionic equation by canceling those items that appear on both sides; i.e., the Cl^- and K^+ to leave you with the net ionic equation of
3Ca^2+(aq) + 2PO4^3-(aq) ==> Ca3(PO4)2(s)

a) The balanced equation for the reaction is:

3CaCl2 + 2K3PO4 → Ca3(PO4)2 + 6KCl

b) The total ionic equation for the reaction is:

3 Ca^(2+) (aq) + 6 Cl^(-) (aq) + 2 K^(+) (aq) + 2 PO4^(3-) (aq) → Ca3(PO4)2 (s) + 6 KCl (aq)

a) The balanced equation for the reaction between calcium chloride and potassium phosphate is:

3 CaCl2 + 2 K3PO4 → Ca3(PO4)2 + 6 KCl

b) The total ionic equation for this reaction can be written by separating the reactants and products into their respective ions:

3 Ca2+ + 6 Cl- + 6 K+ + 2 PO43- → Ca3(PO4)2 + 6 K+ + 6 Cl-

To answer these questions, we need to understand the chemical equations involved and the physical states of the reactants and products.

a) Writing the balanced equation:
The given information states that calcium chloride (CaCl2) reacts with potassium phosphate (K3PO4) to form calcium phosphate (Ca3(PO4)2) and potassium chloride (KCl). Let's write the balanced chemical equation for this reaction:

3CaCl2 + 2K3PO4 → Ca3(PO4)2 + 6KCl

b) Determining the total ionic equation:
To write the total ionic equation, we must identify which compounds dissociate into ions in solution.

In this case, calcium chloride (CaCl2) and potassium chloride (KCl) are both ionic compounds and dissociate into ions when dissolved in water.

The balanced equation can be rewritten in its ionic form as follows:

3Ca^2+(aq) + 6Cl^-(aq) + 2K^+(aq) + PO4^3-(aq) → Ca3(PO4)2(s) + 6K^+(aq) + 6Cl^-(aq)

In this equation, the (aq) notation represents the species as dissolved in water, and (s) represents the solid precipitate formed.

This total ionic equation shows all ions involved in the reaction separately.

Note: It's important to remember that the total ionic equation includes all species, even though some of them are not directly involved in the reaction.