A hill in the Tour de France bike race has a grade of 8%. To the nearest degree, what is the angle that this hill makes with the horizontal ground? Round to the nearest tenth of a degree.

8% = 8/100 = .08

so tanØ = .08
Ø = 4.57
= 4.6° to the nearest tenth

Liola drives 25 km up a hill that is at a grade of .

To find the angle that a hill with a grade of 8% makes with the horizontal ground, we can use the trigonometric function tangent (tan). The tangent of an angle can be found by dividing the vertical height (rise) by the horizontal distance (run).

In this case, the grade of the hill is given as 8%, which means there is an 8-unit rise for every 100 units of horizontal distance. We can interpret this as a rise of 8 meters for every 100 meters of run.

Let's calculate the angle using the formula:

angle = arctan(rise / run)

Plugging in the values, we have:

angle = arctan(8 / 100)

Using a calculator, the arctan(8 / 100) is approximately 4.76 degrees.

Therefore, to the nearest degree, the angle that this hill makes with the horizontal ground is 5 degrees.

To find the angle that the hill makes with the horizontal ground, we can use trigonometry. The grade of the hill is given as 8%.

The grade of a hill represents the ratio of the vertical change to the horizontal distance. In this case, the grade is 8%, which means that for every 100 units of horizontal distance, there is a vertical change of 8 units.

To find the angle, we need to calculate the inverse tangent of the grade. The inverse tangent function (also known as arctan) gives us the angle when we know the ratio of the opposite side to the adjacent side of a right triangle.

Using the formula:

angle = arctan(grade)

We can substitute in the given grade:

angle = arctan(8%)

Now, let's calculate the angle using a calculator or a programming language:

arctan(8%) ≈ 4.76 degrees

Therefore, to the nearest degree, the angle that the hill makes with the horizontal ground is 5 degrees.