A box contains 8 blue balls, 3 white balls, and 5 red balls, and that we choose two balls at random from the box.
What is the probability of neither being blue given that neither is white?
12
To calculate the probability of neither ball being blue given that neither ball is white, we need to consider the number of favorable outcomes and the total number of possible outcomes.
First, let's determine the total number of possible outcomes. Since we are choosing two balls at random from the box, there are a total of (8 + 3 + 5) = 16 balls in total.
Next, let's calculate the number of favorable outcomes, i.e., the cases where neither ball is blue given that neither ball is white. Since we are excluding white balls, we need to consider the remaining blue and red balls, which is a total of (8 + 5) = 13 balls.
Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes
Probability = 13 / 16
Therefore, the probability of neither ball being blue given that neither is white is 13/16.