A dog travels at a rate of 4m/s[S] in a train car that is moving 12m/s[N]. Find the dog's velocity relative to the ground.
V3=4.0 m/s S
V2=12 m/s N
V1=?
object and object not moving= V1
Moving object and object not moving= V3
object and moving object= V2
V1=V2+V3
square v2 and dd it to squared of V3
V1= 144+16
V1= 160
square root of 60 is
12.4
so the answer is 12.4 m/s N