A telephone long-distance carrier charges customers $0.99 for the first 20 minutes and then $0.06 for each minute(or any part thereof) beyond 20 minutes. If Mary uses this carrier,how long can she talk for $4.00?
I started off with 0.99x+20+0.06x=4.00. PLEASE help, I don't think I set it up correctly.
You estimate 547= 540 and 92= 90.So now divide 540/90 and there you got your answer.
60 is your answer
where do you get 547 and 92 from?
first 20min
.99x
.99*20=19.8
after 20min
0.06x+19.8
$4 is less than 19.8
so the answer would be .99x=4
x=4/.99
x=4.04
To solve this problem, you need to set up an equation using the given information.
Let's break down the problem step by step:
1. The cost for the first 20 minutes is $0.99.
2. After the first 20 minutes, there is an additional cost of $0.06 for each minute (or any part thereof). This means that even if you talk for only a fraction of a minute after the first 20 minutes, you still get charged $0.06.
3. You are given that Mary has $4.00 to spend on the call.
Let's set up the equation:
The cost of the first 20 minutes: $0.99
The cost of the remaining minutes: $0.06 per minute (or part thereof)
Let's assume Mary talks for "x" minutes after the first 20 minutes. Therefore, the total cost of the call is:
$0.99 (for the first 20 minutes) + $0.06x (for the remaining minutes) = $4.00
Now, let's set up the equation:
0.99 + 0.06x = 4.00
To solve it, subtract 0.99 from both sides of the equation:
0.06x = 4.00 - 0.99
0.06x = 3.01
Divide both sides of the equation by 0.06:
x = 3.01 / 0.06
x ≈ 50.17
Therefore, Mary can talk for approximately 50.17 minutes with $4.00 using this long-distance carrier.