A long-haired cat (recessive trait s) is crossed with a heterocygous short-haired cat (dominant trait S). What percentage of their offspring will have long hair?
A. 100 percent
B. 50 percent
C. 25 percent
D. 0 percent
Is the answer C?
I need some help
No.
Long-haired = ss
Short-haired = Ss
Use Punnett square.
https://www.google.com/search?client=safari&rls=en&q=punnett+square+worksheet&ie=UTF-8&oe=UTF-8&gws_rd=ssl
To determine the percentage of offspring with a specific trait, we can use Punnett squares. In this case, we are crossing a long-haired cat (ss) with a heterozygous short-haired cat (Ss).
In a Punnett square, we list the possible alleles from each parent on the top and left side, and then combine them to determine the possible genotypes of the offspring.
The possible gametes for the long-haired cat (ss) are all s, and for the short-haired cat (Ss) are S and s.
Using a Punnett square:
S s
s | Ss | ss
From the Punnett square, we can see that there are two possible genotypes for the offspring: Ss and ss.
The genotype Ss represents short hair, as the dominant allele S will determine the trait. The genotype ss represents long hair, as it only contains the recessive allele s.
Since only one out of the four possible combinations (Ss and ss) results in long hair, the answer is 25 percent. Therefore, the correct answer is C.