A piston of a car engine executes a simple harmonic motion.

the acceleration a of the piston is related to its displacement x by the equation:
a = -6.4*10^5x
a) Calculate the frequency of motion
b) The piston has a mass of 700 gms & a max displacement of 8 cm.
Calculate the max force on the pistion.

To calculate the frequency of motion, we can use the equation:

f = (1 / T)

where f is the frequency and T is the period of motion.

In this case, the motion is simple harmonic motion, and we know that the period T is related to the angular frequency ω by the equation:

T = 2π / ω

The angular frequency is related to the acceleration a by the equation:

a = -ω^2 * x

Comparing this equation with the given equation a = -6.4 * 10^5x, we can see that ω^2 = 6.4 * 10^5. Taking the square root of both sides, we get:

ω = √(6.4 * 10^5)

Now we can substitute this value of ω into the equation for T to find the period T. Then, we can use the equation for frequency f to calculate the frequency.

a) Calculate the frequency of motion:

In our case, ω = √(6.4 * 10^5)

T = 2π / ω

T = 2π / √(6.4 * 10^5)

f = 1 / T

Substituting the value of T, we get:

f = 1 / (2π / √(6.4 * 10^5))

Simplifying further, we get:

f = √(6.4 * 10^5) / (2π)

Evaluating this expression, we find:

f ≈ 89.44 Hz

So, the frequency of motion is approximately 89.44 Hz.

b) Calculate the max force on the piston:

The maximum force on the piston can be calculated using Hooke's Law, which states that the force (F) is equal to the mass (m) multiplied by the acceleration (a):

F = m * a

Given that the mass of the piston is 700 gms (or 0.7 kg) and the maximum displacement (x) is 8 cm (or 0.08 m), we can use the given equation for acceleration (a = -6.4 * 10^5x) to calculate the maximum force (F).

Substituting the given values into the equation, we get:

a (at maximum displacement) = -6.4 * 10^5 * 0.08

F = (0.7 kg) * (-6.4 * 10^5 * 0.08)

Evaluating this expression, we find:

F ≈ -322,560 N

The negative sign indicates that the force is in the opposite direction of the displacement. So, the maximum force on the piston is approximately 322,560 N.

a)0.15