Determine the number of valence electron and the oxidation numbers for each of the following atoms.
1. Pb atomic #82
#valence e-'s=
oxidation# =
To determine the number of valence electrons for an atom, we need to identify its group number on the periodic table. For Pb (atomic number 82), it is located in group 14.
In group 14, the valence electron configuration can be determined by looking at the last digit of the group number. In this case, the last digit is 4. Therefore, lead (Pb) has 4 valence electrons.
Next, let's determine the oxidation number for Pb. The oxidation number refers to the charge an atom would have if all its bonds were completely ionic.
Pb belongs to the p-block elements, which typically have oxidation numbers ranging from -3 to +5 (except for the noble gases). However, for the main group elements like Pb, the oxidation number is often equal to the group number (with some exceptions).
Since Pb is in group 14, the oxidation number of lead is +4.
So, the number of valence electrons for Pb is 4, and its oxidation number is +4.