1.3 mol of calcium carbonate decomposed to calcium oxide and carbon dioxide. How many grams of calcium oxide is produced?
To find the number of grams of calcium oxide produced, we need to use the molar mass and balanced equation for the decomposition of calcium carbonate.
The balanced equation for the decomposition of calcium carbonate is:
CaCO3 -> CaO + CO2
From the equation, we can see that the molar ratio between calcium carbonate and calcium oxide is 1:1. This means that for every 1 mol of calcium carbonate decomposed, we will obtain 1 mol of calcium oxide.
Given that we have 1.3 mol of calcium carbonate, we can conclude that we will also obtain 1.3 mol of calcium oxide.
Next, we need to calculate the molar mass of calcium oxide (CaO). The atomic mass of calcium (Ca) is approximately 40.08 g/mol, and the atomic mass of oxygen (O) is approximately 16.00 g/mol. Adding these values together, we get the molar mass of calcium oxide:
Molar mass of CaO = (1 × 40.08 g/mol) + (1 × 16.00 g/mol) = 56.08 g/mol
Finally, we can calculate the number of grams of calcium oxide produced by multiplying the number of moles by the molar mass:
Grams of CaO produced = 1.3 mol × 56.08 g/mol
Hence, the number of grams of calcium oxide produced is 72.91 grams.