if the coeffiecient of friction between a 32kg metal plate and the floor is 0.16, what force is required to roll this metal plate across the floor at a uniform speed? how much work is done if the metal plate is rolled to a distance of 15m?

Please response i need your help.

To determine the force required to roll the metal plate across the floor at a uniform speed, we need to consider the frictional force acting between the plate and the floor. The formula for frictional force is given by:

Frictional Force = coefficient of friction * Normal Force

The normal force is equal to the weight of the object, which is given by:

Weight = mass * gravitational acceleration

Using the data provided, the mass of the metal plate is 32 kg. The gravitational acceleration is approximately 9.8 m/s².

Weight = 32 kg * 9.8 m/s² = 313.6 N

The frictional force can be calculated as:

Frictional Force = 0.16 * 313.6 N = 50.176 N

Since the plate is moving at a uniform speed, the applied force must be equal in magnitude and opposite in direction to the frictional force. Therefore, the force required to roll the metal plate across the floor at a uniform speed is approximately 50.176 N.

To calculate the work done in rolling the metal plate a distance of 15 m, we can use the formula:

Work = force * distance * cos(theta)

In this case, theta is the angle between the applied force (frictional force) and the direction of motion, which is 0 degrees since they are in the same direction.

Work = 50.176 N * 15 m * cos(0°) = 752.64 J

Therefore, the work done in rolling the metal plate to a distance of 15 m is approximately 752.64 joules.