I want to make up a 180g/l solution acid using 98% Sulphuric Acid. How much H2SO4 do I use should I make a stock solution first.

Well, well, well, if it isn't my favorite chemist in town! So, you want to make a 180g/l solution of acid using 98% Sulphuric Acid? Let me crunch some numbers and sprinkle some humor for you.

Since you want a 180g/l concentration, you'll need to dissolve 180 grams of Sulphuric Acid in a liter of solution. Now, since your Sulphuric Acid is 98% pure, you’ll need to take that into account.

To calculate the amount of 98% Sulphuric Acid needed, you can use the following formula:

(180g/l) / (0.98) = X

Where X is the amount of pure Sulphuric Acid you need to use to achieve a 180g/l concentration. Remember, this will give you the volume of Sulphuric Acid needed to make a liter of solution.

And as for making a stock solution first, well, it's entirely up to you! If you're planning to use this solution for multiple experiments or future use, a stock solution might be a good idea. Just make sure to label it clearly so nobody accidentally confuses it with their morning coffee!

Hope that helps, my chemistry-loving friend!

To make a 180g/l solution of sulfuric acid using 98% sulfuric acid, you will need to determine the volume of the stock solution and the amount of concentrated sulfuric acid required.

1. Calculate the amount of sulfuric acid required:
First, convert the desired concentration from grams per liter (g/l) to moles per liter (mol/l):
180 g/l / (molar mass of H2SO4) = X mol/l

The molar mass of sulfuric acid (H2SO4) is:
1(2) + 32 + 16(4) = 98 g/mol

So, the concentration in moles per liter (mol/l) is:
180 g/l / 98 g/mol ≈ 1.84 mol/l

2. Determine the volume of the stock solution:
To calculate the volume of the stock solution, you need to decide the final volume you want to prepare. Let's assume you want to prepare 1 liter (1000 ml) of the solution.

3. Calculate the amount of concentrated sulfuric acid required:
To find the amount of concentrated sulfuric acid needed, use the equation:
(concentration of stock solution) × (volume of stock solution) = (concentration of concentrated sulfuric acid) × (volume of concentrated sulfuric acid)

Let's denote the concentration of the stock solution as C1, the volume of the stock solution as V1, the concentration of the concentrated sulfuric acid as C2, and the volume of the concentrated sulfuric acid as V2.

Using the equation above:
C1 × V1 = C2 × V2

Substituting the known values:
(1.84 mol/l) × (V1) = (0.98 mol/l) × (V2)

Since the concentration of 98% sulfuric acid is 0.98 mol/l, and we are assuming we have 1 liter of stock solution:
(1.84 mol/l) × (1 liter) = (0.98 mol/l) × (V2)

Solving for V2:
V2 = (1.84 mol/l × 1 liter) / 0.98 mol/l
V2 ≈ 1.878 liters

Therefore, you would need approximately 1.878 liters of 98% sulfuric acid to prepare 1 liter of a 180g/l sulfuric acid solution.

To make a 180g/L solution of sulfuric acid using 98% sulfuric acid, you will need to calculate how much sulfuric acid you should use. Before we proceed, a stock solution is not necessary for this particular case.

Here's how you can calculate it step by step:

Step 1: Determine the desired mass of sulfuric acid in one liter of the solution.
The desired concentration is 180g/L, which means you want 180 grams of sulfuric acid in one liter of the solution.

Step 2: Calculate the volume of pure sulfuric acid needed.
To determine the volume of pure sulfuric acid needed, divide the desired mass by the concentration (percentage) of the sulfuric acid. In this case, the concentration is 98%.

(180 g) / (98%) = 183.67 g

Step 3: Convert grams to milliliters.
Sulfuric acid is a dense liquid, so its weight in grams is equal to its volume in milliliters (approx.). Therefore, the amount of sulfuric acid you need is approximately 183.67 mL.

So, to make a 180g/L solution of sulfuric acid using 98% sulfuric acid, you should use approximately 183.67 mL of the acid in one liter of water. Measure the sulfuric acid carefully and then add it to the water while stirring slowly. Always remember to add acid to water, not water to acid, to prevent splashing or reactions.