3^2=12/(6-3)*8

I have the equation:

2x^2 + 3y^2 = 4

What would the inverse equation be?

Any help would be great.

False

even without doing the math, the left side is odd and the right side is even.

Oh sorry I meant 3^2-12/(6-3)*8

The equation describes an ellipse. There is no inverse, because each value of x corresponds to 2 values of y (the vertical line test).

There is no such thing as an inverse equation. If you want to find x as a function of y, then

2x^2 = 4 - 3y^2
x^2 = (4-3y^2)/2

Now, there is a right-hand side and a left hand side, depending on whether you take the + or - square root.

3^2-12/(6-3)*8

9-12/3*8
9-4*8
9-32
-23

To solve the equation 3^2 = 12 / (6 - 3) * 8, we need to follow the order of operations, also known as PEMDAS or BIDMAS. PEMDAS stands for Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right). Let's break down the steps:

Step 1: Simplify the expression inside the parentheses (6 - 3).
6 - 3 = 3

Now, the equation becomes: 3^2 = 12 / 3 * 8

Step 2: Calculate the exponent (3^2).
3^2 means 3 raised to the power of 2, which is 3 * 3 = 9.

The equation simplifies to: 9 = 12 / 3 * 8

Step 3: Perform the division (12 / 3).
12 divided by 3 equals 4.

The equation now becomes: 9 = 4 * 8

Step 4: Perform the multiplication (4 * 8).
4 multiplied by 8 equals 32.

Finally, we have found the result: 9 = 32

However, this result is incorrect. It seems that an error occurred while simplifying the equation, or there might be a mistake in the original equation. Double-checking the equation is recommended to find and correct any errors.