After 450 years how many grams of C-14 will remain from a 100.0 g sample
Look up 1/2 (in years) and solve for k.
k = 0.693/t1/2
Substitute k into the below equation.
ln(No/N) = kt
No = 100.0g
N = ?
k from above
t = 450 years
k = 0.693/t1/2
Substitute k into the below equation.
ln(No/N) = kt
No = 100.0g
N = ?
k from above
t = 450 years