NaI(aq)+Hg2(C2H3O2)2(aq)→
2NaI(aq) + Hg2(C2H3O2)2(aq) ==> Hg2I2(s) + 2NaC2H3O2(aq)
Oh boy, looks like we've got a chemistry question! Let me see if I can come up with a humorous response for you.
Ahem, okay, here it is:
When NaI goes on a date with Hg2(C2H3O2)2, things can get pretty interesting! It's like two chemicals coming together for a wild night out. Will they form a new compound? Will there be sparks (or sparks in this case)? Who knows! Chemistry can be just as unpredictable as love. So, sit back and enjoy the reaction, because when it comes to chemistry, it's always a mystery!
To write the complete ionic equation for the given chemical reaction between sodium iodide (NaI) and mercury(II) acetate (Hg2(C2H3O2)2), we first need to know the state of each compound. I will assume that NaI and Hg2(C2H3O2)2 are both in aqueous solution.
The balanced chemical equation for the reaction is:
2 NaI(aq) + Hg2(C2H3O2)2(aq) → 2 NaC2H3O2(aq) + Hg2I2(s)
Here's the step-by-step breakdown of how to balance the equation:
Step 1: Write down the reactants and products.
NaI(aq) + Hg2(C2H3O2)2(aq) → NaC2H3O2(aq) + Hg2I2(s)
Step 2: Balance the metals first (in this case, Hg).
Since there are two Hg atoms in Hg2(C2H3O2)2 and only one Hg atom in Hg2I2, we need to balance the Hg by placing a coefficient of 2 in front of Hg2I2.
NaI(aq) + Hg2(C2H3O2)2(aq) → NaC2H3O2(aq) + 2 Hg2I2(s)
Step 3: Balance the iodine (I) atoms.
There are two iodine atoms on the left side of the equation (2 NaI) and four iodine atoms on the right side (2 Hg2I2). To balance the iodine atoms, place a coefficient of 2 in front of NaI.
2 NaI(aq) + Hg2(C2H3O2)2(aq) → NaC2H3O2(aq) + 2 Hg2I2(s)
Step 4: Balance the sodium (Na) and acetate (C2H3O2) ions.
There are now two sodium ions (2 Na) and two acetate ions (2 C2H3O2) on the right side. Thus, the equation is already balanced.
The final balanced chemical equation is:
2 NaI(aq) + Hg2(C2H3O2)2(aq) → 2 NaC2H3O2(aq) + 2 Hg2I2(s)
Note: This is the balanced equation, but if you require the full ionic equation, it will involve writing out the dissociated forms of the soluble compounds.
The given chemical equation represents a reaction between sodium iodide (NaI) dissolved in water (aqueous solution) and mercury(II) acetate (Hg2(C2H3O2)2) dissolved in water.
To understand what happens in this reaction, we need to consider the properties and behavior of the reactants. Sodium iodide (NaI) is an ionic compound composed of sodium (Na+) cation and iodide (I-) anion. It readily dissolves in water, dissociating into sodium ions (Na+) and iodide ions (I-).
Mercury(II) acetate (Hg2(C2H3O2)2), on the other hand, is a compound composed of mercury (Hg2+) cation and acetate (C2H3O2-) anions. Similar to sodium iodide, it also dissolves in water, breaking apart into its component ions.
Based on the reactants' solubility and dissociation, we can assume that the reaction takes place in an aqueous solution. The reaction between sodium iodide (NaI) and mercury(II) acetate (Hg2(C2H3O2)2) can be written as follows:
2 NaI(aq) + Hg2(C2H3O2)2(aq) → 2 NaC2H3O2(aq) + HgI2(s)
In this reaction, sodium iodide reacts with mercury(II) acetate to produce sodium acetate and solid mercury(II) iodide. The chemical equation is balanced, indicating that two moles of sodium iodide react with one mole of mercury(II) acetate to form two moles of sodium acetate and one mole of mercury(II) iodide.
If you want to further understand the reaction, you can balance the equation using the appropriate coefficients, taking into account the conservation of matter.
Note: It's important to handle mercury compounds with caution as mercury is a toxic substance.