A baseball is thrown upward with an initial speed of 35 m/s. What is the speed at t = 2 s?
To find the speed at t = 2 s, we can use the kinematic equation for velocity:
v = u + at
where:
v is the final velocity,
u is the initial velocity,
a is the acceleration, and
t is the time interval.
In this case, considering the ball is thrown upward, the initial velocity (u) is 35 m/s, the acceleration (a) due to gravity is -9.8 m/s² (negative because it acts in the opposite direction of the motion), and the time interval (t) is 2 s.
Substituting the given values into the equation:
v = 35 m/s + (-9.8 m/s²) × 2 s
First, calculate the acceleration multiplied by time:
(-9.8 m/s²) × 2 s = -19.6 m/s
Then, substitute this value back into the equation:
v = 35 m/s - 19.6 m/s = 15.4 m/s
Therefore, the speed of the baseball at t = 2 s is 15.4 m/s.