Suppose that the scores on a reading ability test are normally distributed with a mean of and a standard deviation of . What proportion of individuals score more than points on this test

To find the proportion of individuals who score more than a certain value on a normally distributed test, we will use the standard normal distribution table or calculator.

First, we need to calculate the z-score for the given value. The z-score represents the number of standard deviations that a particular value is away from the mean. We can calculate the z-score using the formula:

z = (x - μ) / σ

where x is the given value, μ is the mean, and σ is the standard deviation.

Let's assume the mean is μ and the standard deviation is σ.

In this case, we want to find the proportion of individuals who score more than a certain value, let's call it x. We'll calculate the z-score for x:

z = (x - μ) / σ

Once we have the z-score, we can use the standard normal distribution table or calculator to find the proportion of individuals who score more than x.

Please provide the values for the mean (μ) and standard deviation (σ) in order to proceed further.