I am a 3-digit number.My tens is 2 times my hundreds my ones is the same as the sum of my tens and hundreds.What number can I be?
246
how many digits r there in 8 tens + 13 ones
To find the number that satisfies the given conditions, let's break down the information provided.
Let's say the hundreds digit is represented by 'H', the tens digit is represented by 'T', and the ones digit is represented by 'O'.
According to the given information:
1. The tens digit is twice the value of the hundreds digit. This can be expressed as T = 2H.
2. The ones digit is equal to the sum of the tens and hundreds digits. This can be expressed as O = T + H.
Now, we need to find the values of H, T, and O that satisfy these conditions.
From the first condition (T = 2H), we can try various values for H and find the corresponding value for T. Let's consider H = 1, 2, 3, and so on.
If H = 1, then T = 2H = 2(1) = 2.
If H = 2, then T = 2H = 2(2) = 4.
If H = 3, then T = 2H = 2(3) = 6.
If H = 4, then T = 2H = 2(4) = 8.
And so on...
Now, let's use the second condition (O = T + H) to find the value of O for each case.
If H = 1, then O = T + H = 2 + 1 = 3. So the number could be 123.
If H = 2, then O = T + H = 4 + 2 = 6. So the number could be 246.
If H = 3, then O = T + H = 6 + 3 = 9. So the number could be 369.
If H = 4, then O = T + H = 8 + 4 = 12. Since we need a single-digit number for the ones place, this doesn't satisfy the conditions.
From the possible combinations, we see that the only valid 3-digit number that satisfies the conditions is 369.
Therefore, the number you could be is 369.