What is the molarity of HCL if it takes 16.5 mL of 0.100 M NaOH to titrate 10.0 mL of HCl?
HCl + NaOH -> H2O + NaCl
molarity = moles of solute/liters of solution
mols NaOH = M x L = ?
mol HCl = mols NaOH (look at the coefficients in the balanced equation)
Then M HCl = mols HCl/L HCl.
To find the molarity of HCl, we can use the balanced chemical equation and the given information about the volume and molarity of NaOH.
First, let's convert the volume of NaOH used to liters:
16.5 mL = 16.5 mL * (1 L / 1000 mL) = 0.0165 L
Next, we can calculate the moles of NaOH used by multiplying the volume (in liters) by the molarity of NaOH:
moles of NaOH = 0.0165 L * 0.100 M = 0.00165 moles
Since the balanced chemical equation shows that NaOH and HCl react in a 1:1 ratio, the moles of HCl will also be 0.00165 moles.
Now, let's convert the volume of HCl used to liters:
10.0 mL = 10.0 mL * (1 L / 1000 mL) = 0.0100 L
Finally, we can use the formula for molarity to find the molarity of HCl:
molarity = moles of solute / liters of solution = 0.00165 moles / 0.0100 L
molarity of HCl = 0.165 M
Therefore, the molarity of HCl is 0.165 M.