A man s;pends 3/8of his money and still has Rs 720 left with him. How much money did he have at first?
(5/8)x = 720
Solve for x
Patanahi
1152
720×3/8
To find out how much money the man had at first, we can use the information given that he spent 3/8 of his money and still had Rs 720 left.
Let's assume the man originally had Rs X.
According to the problem, he spent 3/8 of his money, which is (3/8) * X = (3X/8).
After spending this money, he still had Rs 720 left, so we can write the equation:
(3X/8) + 720 = X
To solve this equation, we can follow the steps:
1. Multiply both sides of the equation by 8 to eliminate the denominator:
8 * ((3X/8) + 720) = 8 * X
3X + 5760 = 8X
2. Subtract 3X from both sides to isolate the variable on one side:
3X - 3X + 5760 = 8X - 3X
5760 = 5X
3. Divide both sides of the equation by 5 to solve for X:
5760/5 = X
1152 = X
Therefore, the man originally had Rs 1152.