Decide whether each equation has one solution, no solutions, or infinitely many solutions. 3(y-3)=2y-9+y
A. One solution
B. No Solutions
C. Infinitely many solutions
I did 3*y
3*3=9
2y=9+4
3-*=-6
x-27
Is the answer A?
3(y-3)=2y-9+y
Distribute the 3
3y-9=2y-9+y
Combine the like terms that are on the right side "2y" and "y"
3y-9=3y-9
You can stop right here because the equations are the same on both sides. This tells you that no matter what y is it will be equal on both sides. Which is why the answer is C.
Did I explain clearly?
3(y - 3) = 2y - 9 + y (Distribute on left side, and combine 2y and y on right side.)
3y - 9 = 3y - 9 (Subtract 3y on both sides.)
3y 3y - 3y - 9 = - 9 (Add 9 to both sides.)
3y - 3y = -9 + 9
0 = 0 (Final result.0
So the answer is C because x could be any number and you'll still get 0 as the final result of the equation.
I hope this helps! :)
___3(y - 3) = 2y - 9 + y (Distribute on left side, and combine 2y and y on right side.)
_____3y - 9 = 3y - 9 - 3y(Subtract 3y on both sides.I meant to put - 3y in the right spot in my first post to help you Gwen.)
3y - 3y - 9 = - 9 (Add 9 to both sides.)
____3y - 3y = -9 + 9
__________0 = 0 (Final result.)
So the answer is C because x could be any number and you'll still get 0 as the final result of the equation.
I hope this helps! :)
To determine whether the equation has one solution, no solutions, or infinitely many solutions, we need to simplify the equation and compare the coefficients of y.
Let's start by simplifying the equation:
3(y-3) = 2y - 9 + y
First, distribute the 3 on the left side of the equation:
3y - 9 = 2y - 9 + y
Next, combine like terms:
3y - 9 = 3y - 9
Now, we can see that both sides of the equation are identical. This means that the equation is an identity and is true for all values of y. In other words, there are infinitely many values of y that satisfy the equation.
Therefore, the answer is C. Infinitely many solutions.