how much copper sulphate will require saturating 80 grams of water at 20 degree celcious .if solubility of copper sulphate at 20degree celcious is 25?
Solubility is defined as the number of grams of solute that will saturate 100 grams of solvent at a given temperature.
So at 20 degrees, we know that the solubility of CuSO4 is 25.
Mass of water (solvent)=80 g
Use ratios:
25:100 = x:80
Solve for x to get x=25*80/100=20g
Well, before I give you an answer, I have a burning question: why would you want to saturate water with copper sulphate? Are you trying to turn it into a fancy-colored cocktail or conduct a magical chemistry experiment? In any case, let me lend a helping hand.
Now, the solubility of copper sulphate at 20 degrees Celsius is 25, which means that 25 grams can dissolve in 100 grams of water. In your case, you have 80 grams of water, so we can set up a simple proportion:
25 grams (solubility) is to 100 grams (water) as X grams (copper sulphate needed) is to 80 grams (water).
If we cross multiply and solve for X, we find that approximately 20 grams of copper sulphate are needed to saturate your 80 grams of water at 20 degrees Celsius. Just remember not to confuse your fancy-colored cocktail with your chemistry experiment!
To calculate the amount of copper sulfate required to saturate 80 grams of water at 20 degrees Celsius, we need to know the solubility of copper sulfate at that temperature. According to the information you provided, the solubility of copper sulfate at 20 degrees Celsius is 25.
The solubility of a substance represents the maximum amount of that substance that can dissolve in a given amount of solvent under specific conditions (such as temperature). Therefore, if the solubility of copper sulfate at 20 degrees Celsius is 25, it means that 25 grams of copper sulfate can dissolve in 100 grams of water at that temperature.
To determine the amount of copper sulfate required to saturate 80 grams of water, we can use a proportion:
(solubility of copper sulfate / solubility of water) = (mass of copper sulfate / mass of water)
Substituting the values:
25 / 100 = x / 80
Solving for x (the mass of copper sulfate needed):
25 * 80 = 100 * x
2000 = 100 * x
x = 2000 / 100
x = 20
Therefore, you will need 20 grams of copper sulfate to saturate 80 grams of water at 20 degrees Celsius.
To determine how much copper sulphate is required to saturate 80 grams of water at 20 degrees Celsius, we need to know the solubility of copper sulphate at that temperature.
The solubility of copper sulphate at 20 degrees Celsius is given as 25. This means that 25 grams of copper sulphate can dissolve in 100 grams of water at that temperature.
To calculate the amount required to saturate 80 grams of water, we can use the following proportion:
Solubility of copper sulphate (g) / 100 g of water = x / 80 g of water
Since the solubility is given as 25 g, we can substitute the values into the equation:
25 g / 100 g = x / 80 g
Now, we can solve for x.
First, cross multiply:
100 g * x = 25 g * 80 g
Then, simplify:
100x = 2000
Finally, solve for x by dividing both sides of the equation by 100:
x = 2000 / 100
x = 20
Therefore, 20 grams of copper sulphate is required to saturate 80 grams of water at 20 degrees Celsius.