How do you write the equation of the line with slope -2 that passes through the point (-1, -3) in slope-intercept form?
Thanks to anyone that helps! :)
start off with the point-slope form, since that is what they gave you:
y+3 = -2(x+1)
and rearrange things to fit the slope-intercept form.
@Steve, can you please explain to me how to do it? Because my teacher really didn't explain it to me and my class very good. Thank you.
To write the equation of a line with a given slope that passes through a given point, you can use the point-slope form of a linear equation. The slope-intercept form of a linear equation is y = mx + b, where m represents the slope and b represents the y-intercept.
Given that the slope is -2 and the point through which the line passes is (-1, -3), we can plug these values into the point-slope form:
y - y1 = m(x - x1)
Here, (x1, y1) corresponds to the coordinates of the given point. Substituting the given values into the equation:
y - (-3) = -2(x - (-1))
Simplifying:
y + 3 = -2(x + 1)
Now, we can convert this equation into slope-intercept form:
y + 3 = -2x - 2
To isolate y, subtract 3 from both sides:
y = -2x - 5
Thus, the equation of the line with slope -2 that passes through the point (-1, -3) is y = -2x - 5.