what is the horizontal distance a slingshot on a 25 m cliff will shoot if it's initial velocity is 240 m/s and it's inclined at 45 degrees

y = 25 + 9.8/(240cos45)^2) x^2 ?

^^would this be the right formula?

To calculate the horizontal distance a projectile will travel, we can use the projectile motion formulas. The formula you have provided seems to be incorrect.

The correct formula to determine the horizontal distance is:

Range = (initial velocity^2 * sin(2θ)) / gravitational acceleration

In this case, the initial velocity is 240 m/s, and the angle of inclination (θ) is 45 degrees. The gravitational acceleration is approximately 9.8 m/s^2.

Here's how to calculate the horizontal distance using the correct formula:

1. Convert the angle from degrees to radians: θ = 45 degrees * (π/180 radians/degree) = π/4 radians.

2. Substitute the given values into the formula:

Range = (240^2 * sin(2 * π/4)) / 9.8

3. Simplify:

Range = (240^2 * sin(π/2)) / 9.8

4. Use the trigonometric identity sin(π/2) = 1:

Range = (240^2 * 1) / 9.8

5. Perform the calculation:

Range ≈ 5,877.55 meters

Therefore, the horizontal distance the slingshot on a 25 m cliff will shoot with an initial velocity of 240 m/s and an inclination angle of 45 degrees is approximately 5,877.55 meters.