A metal bar having a mass of 212 g is heated to 125.0°C and then dropped into 375 g of water at 24°C. After a while the temperature of the water and the metal is 34.2°C. If the specific heat of the metal is 0.831 J/g°C, how much heat did the metal lose?
Please help me! Thank you I really appreciate it! :)
I just answered your question WAAAAY down below at your first post.
To determine how much heat the metal lost, we can use the equation:
Q = m * c * ΔT
Q: amount of heat lost (in joules)
m: mass of the metal (in grams)
c: specific heat of the metal (in J/g°C)
ΔT: change in temperature (in °C)
First, let's calculate the change in temperature for the metal:
ΔT = final temperature - initial temperature
ΔT = 34.2°C - 125.0°C
ΔT = -90.8°C
Since the temperature difference is negative, it means that the metal lost heat.
Now we can substitute the known values into the equation:
Q = 212 g * 0.831 J/g°C * (-90.8°C)
To calculate the heat lost by the metal, simply plug in these values and perform the calculation:
Q = -167,949.984 J
Therefore, the metal lost approximately 167,950 J of heat.