a gold bar weighing 33.5 g and having an initial temperature of 25.0 Celsius absorbs 5000 J of heat. What would the new temperature be?
5000 = (specific heat of gold)(T-25)(33.5)
Thank you SOOO much, Damon! I used the formula that you gave, and I got the answer right! I am beyond grateful! :)
I dont quite understand, what are you doing with the 5000 J? In my book it says to divide but I dont know why
So, what is the actual answer? Because I keep getting an answer over 100 and i do not think that is correct.
To find the new temperature of the gold bar after absorbing heat, we need to use the equation:
Q = mcΔT
Where:
Q is the heat transferred to the gold bar (in Joules)
m is the mass of the gold bar (in grams)
c is the specific heat capacity of gold (in J/g°C)
ΔT is the change in temperature (in °C)
First, we need to find the specific heat capacity of gold. The specific heat capacity of gold is approximately 0.129 J/g°C.
Now we can rearrange the equation to solve for ΔT:
ΔT = Q / (mc)
Plugging in the values:
Q = 5000 J
m = 33.5 g
c = 0.129 J/g°C
ΔT = 5000 J / (33.5 g * 0.129 J/g°C)
Calculating the result:
ΔT = 11.94 °C (rounded to two decimal places)
To find the new temperature, we add the change in temperature to the initial temperature:
New temperature = Initial temperature + ΔT
New temperature = 25.00 °C + 11.94 °C
Calculating the result:
New temperature = 36.94 °C (rounded to two decimal places)
Therefore, the new temperature of the gold bar would be approximately 36.94 °C.