Ms Boyd leads tha national math club at the middle school where she teaches. At the first club meetting of the school year ,60% of the students in attendance were boys.If there was one fewer girl then boy in attendance, how maby students attended the first club meeting
If 60% were boys, the ratio of boys:girls = 3:2
So,
b/(b-1) = 3/2
2b = 3b-3
b = 3
So, 3 boys, 2 girls
60% boys
5 students
To find out how many students attended the first club meeting, we need to use the information given in the question.
Let's say the number of boys in attendance is "B" and the number of girls in attendance is "G".
According to the question, 60% of the students in attendance were boys. This means that 60% of the total number of students is equal to the number of boys:
B = 0.6(Total number of students)
It is also given that there was one fewer girl than boy in attendance:
G = B - 1
To find the total number of students, we need to add the number of boys and girls together:
Total number of students = B + G
Now, we can substitute the value of B in terms of the total number of students in the equation from the first statement:
Total number of students = 0.6(Total number of students) + G
We also have the equation for the number of girls:
G = B - 1
To solve this system of equations, we can substitute the value of G in the equation for the total number of students:
Total number of students = 0.6(Total number of students) + (B - 1)
Now, we can solve for the total number of students:
Total number of students - 0.6(Total number of students) = B - 1
0.4(Total number of students) = B - 1
Total number of students = (B - 1) / 0.4
Since we don't have the exact values for B or the total number of students, we cannot determine the exact number of students who attended the first club meeting. However, we can calculate the number of students based on different scenarios by assigning values to B.