A military jet is flying with uniform motion at 9.3*10^2 m/s[S], the magnitude of which is approximately Mach 2.7. At time zero, it passes a mountain top, which is used as the reference point for this question.
a)Construct a table showing the plane's position relative to the mountain top at the end of each second for a 12 s period. <- i don't get how to do this
To construct a table showing the plane's position relative to the mountain top at the end of each second for a 12-second period, you need to understand the concept of uniform motion and how to calculate the position of an object.
Uniform motion means that the velocity of the object remains constant, so the plane will be traveling at a speed of 9.3 * 10^2 m/s[S] for the entire 12-second period.
To calculate the position of the plane at different time intervals, you can use the formula:
Position = Initial Position + Velocity x Time
In this case, the initial position is the mountain top, which we can assume is at a position of 0 meters.
Now let's construct the table for the plane's position relative to the mountain top at the end of each second for a 12-second period:
| Time (s) | Position (m) |
|----------|--------------|
| 0 | 0 |
| 1 | 9.3 * 10^2 |
| 2 | 1.86 * 10^3 |
| 3 | 2.79 * 10^3 |
| 4 | 3.72 * 10^3 |
| 5 | 4.65 * 10^3 |
| 6 | 5.58 * 10^3 |
| 7 | 6.51 * 10^3 |
| 8 | 7.44 * 10^3 |
| 9 | 8.37 * 10^3 |
| 10 | 9.3 * 10^3 |
| 11 | 1.02 * 10^4 |
| 12 | 1.11 * 10^4 |
To calculate the positions, multiply the velocity (9.3 * 10^2 m/s) by the corresponding times (0, 1, 2, ...) and add these values to the initial position of 0 meters. This will give you the position of the plane relative to the mountain top at each time interval.