How many liters of water should be evaporated from 110 liters of a 12% saline solution so that the solution that remains is a 20% saline solution
To solve this problem, we need to determine how many liters of pure water should be evaporated from the initial 110 liters of a 12% saline solution.
Let's break down the problem into steps:
Step 1: Determine the initial amount of salt in 110 liters of the 12% solution.
The initial amount of salt can be calculated by multiplying the volume of the solution by the percentage concentration of salt:
Initial amount of salt = 110 liters * 12% = 13.2 liters
Step 2: Determine the final volume of the solution.
Since the concentration is given as a percentage of saline in the remaining solution, we can set up the equation:
(13.2 liters of salt) / (final volume of solution) = 20%
This can be rearranged to:
final volume of solution = (13.2 liters of salt) / (20%)
Step 3: Determine the volume of water that should be evaporated.
To find the volume of water that needs to be evaporated, subtract the final volume of the solution from the initial volume:
Volume of water to be evaporated = (initial volume of solution) - (final volume of solution)
Volume of water to be evaporated = 110 liters - [(13.2 liters of salt) / (20%)]
Now, let's calculate the volume of water to be evaporated:
Volume of water to be evaporated = 110 liters - [(13.2 liters) / (0.20)]
Volume of water to be evaporated = 110 liters - 66 liters
Volume of water to be evaporated = 44 liters
So, 44 liters of water should be evaporated from the initial 110 liters of a 12% saline solution in order to obtain a 20% saline solution.