i am a 4 digit odd number none of the numbers are 0-9 the tens digit is twice the ones digit the hundreds digit is twice the tens digit and the thousands digit is one less than the hundreds digit

What do you mean by this?

" none of the numbers are 0-9 "

To solve this problem, we'll break down the information given and find the value of each digit in the 4-digit odd number.

Let's start by assigning variables to each digit:
- Thousands digit: Let's call this digit "A".
- Hundreds digit: Let's call this digit "B".
- Tens digit: Let's call this digit "C".
- Ones digit: Let's call this digit "D".

Now, let's use the given information to create equations:

1) The number is odd: Since the number is odd, the ones digit (D) must be an odd number. Let's consider D = 1, 3, 5, 7, or 9.

2) The tens digit (C) is twice the ones digit (D): Let's write this as an equation: C = 2D.

3) The hundreds digit (B) is twice the tens digit (C): Let's write this as an equation: B = 2C.

4) The thousands digit (A) is one less than the hundreds digit (B): Let's write this as an equation: A = B - 1.

Now, let's solve these equations step by step:

From equation 2) C = 2D. We can substitute this value of C into equation 3):
B = 2C = 2(2D) = 4D.

Next, we substitute the value of B = 4D into equation 4):
A = B - 1 = (4D) - 1 = 4D - 1.

Now, we have expressions for all the digits in terms of D. We know that D is an odd digit, so let's substitute the possible values for D (1, 3, 5, 7, and 9) into the expressions for A, B, C, and D:

For D = 1:
A = 4(1) - 1 = 3
B = 4(1) = 4
C = 2(1) = 2
D = 1

For D = 3:
A = 4(3) - 1 = 11
B = 4(3) = 12
C = 2(3) = 6
D = 3

For D = 5:
A = 4(5) - 1 = 19
B = 4(5) = 20
C = 2(5) = 10
D = 5

For D = 7:
A = 4(7) - 1 = 27
B = 4(7) = 28
C = 2(7) = 14
D = 7

For D = 9:
A = 4(9) - 1 = 35
B = 4(9) = 36
C = 2(9) = 18
D = 9

We observe that in all cases, A, B, C, and D are all greater than 9, which contradicts the given information. Therefore, there are no 4-digit odd numbers that satisfy the conditions provided.

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