Posted by **Gaby** on Thursday, September 11, 2014 at 5:35pm.

When the Sun is directly overhead, a hawk dives toward the ground with a constant velocity of 4.80 m/s at 50.5° below the horizontal. Calculate the speed of her shadow on the level ground.

What i have done:

x= rcos(theta)

x=4.80m/s*cos(309.5)

x=3.05m

y=rsin(theta)

y=4.80m/s*sin(309.5)

y=-3.70m

i know to calculate speed the equation is v=d/t but there is no time stated in the problem... I came to the conclusion that the constant velocity is the speed, is that right?