What is the factor of x^2+8x+8 ?

Thank you ! :)

didn't I just do this? http://www.jiskha.com/display.cgi?id=1410350888

start with...

x^2+8x+8=0

then
x^2+8x+8+8=8
x^2+8x+16=8
(x+4)^2=(2sqrt2)^2
x+4=+-2sqrt2
x= -4 +2sqrt2, and x=-4 -2sqrt 2
(x+4-2sqrt2)(x+4+2sqrt2)

To find the factors of the given quadratic expression, x^2 + 8x + 8, we need to factorize it.

Step 1: The general form of a quadratic equation is ax^2 + bx + c, where a, b, and c are constants.
In this case, a = 1, b = 8, and c = 8.

Step 2: To factorize the quadratic expression, we need to find two numbers whose product is equal to the product of a and c, and whose sum is equal to b.

In this case, the product of a and c is 1 * 8 = 8.

Step 3: We need to find two numbers whose product is 8 and whose sum is 8. The numbers are 2 and 4:

2 * 4 = 8
2 + 4 = 6

Step 4: Using the two numbers we found, we can rewrite the quadratic expression as follows:
x^2 + 8x + 8 = (x + 2)(x + 4)

Therefore, the factors of x^2 + 8x + 8 are (x + 2) and (x + 4).