the sum of three consecutive odd integers is 435. What is the largest of the three integers??how do I solve this problem?? Please help

To solve this problem, we need to utilize the information given: the sum of three consecutive odd integers is 435.

Let's assume the first odd integer as x. Since the integers are consecutive odd numbers, the second odd integer will be x + 2, and the third odd integer will be x + 4.

To find the sum of these three consecutive odd integers, we add them together:

x + (x + 2) + (x + 4) = 435

Now, we combine like terms:

3x + 6 = 435

Next, we isolate the variable x by subtracting 6 from both sides:

3x = 429

Finally, divide both sides by 3:

x = 429 / 3
x = 143

Therefore, the first odd integer is 143.

To find the largest of the three integers, we add 4 to the first odd integer:

143 + 4 = 147

So, the largest of the three consecutive odd integers is 147.

Here's a start:

435/3 = ?

The sum of three consecutive odd integers is 435 Find the three integers.

odd numbers differ be 2

let the first of the odd numbers be x
then the next two odds are x+2, and x+4

x + x+2 + x+4 = 435
3x = 429
x = 143

so the largest is x+4 = 143+4 = 147