What are the orbital used in the formation of [COCL4]^2- ?explain this..
Do you mean [CoCl4]^2-
https://www.google.com/search?q=[COCl4[^2-&client=firefox-a&hs=ryD&rls=org.mozilla:en-US:official&channel=sb&tbm=isch&tbo=u&source=univ&sa=X&ei=IqsPVLOsIoPPggSSyYCwCA&ved=0CCcQsAQ&biw=1007&bih=601
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That shows a tetrahedral structure; therefore, it must be sp3 if you meant Co and not CO
Yes. It is Co.. Sorry for my wrong
To determine the orbitals involved in the formation of the [CoCl4]^2- complex, we need to consider the ligands (Cl-) and the central metal atom (Co). The complex is called tetrachlorocobaltate(II).
In this complex, cobalt (Co) is in the +2 oxidation state, which means it has lost two electrons. Cobalt has an electronic configuration of [Ar]3d^74s^2, where [Ar] represents the electron configuration of the noble gas argon.
The tetrachlorocobaltate(II) complex is formed through the hybridization of the d orbitals of the central cobalt atom with the overlapping orbitals of the ligands.
The cobalt atom undergoes sp3 hybridization, which means that one 3d orbital and three 4s orbitals mix to form four equivalent hybrid orbitals called sp3 hybrid orbitals. These sp3 hybrid orbitals have a tetrahedral arrangement around the cobalt atom.
Each chloride ion (Cl-) has three pairs of non-bonding electrons. These electron pairs occupy three of the sp3 hybrid orbitals of the cobalt atom, forming three sigma (σ) bonds between the cobalt and the chlorides.
The remaining unhybridized d orbital of cobalt, which is perpendicular to the plane of the three sigma bonds, interacts with the remaining empty p orbital of one chlorine atom to form a pi (π) bond. This interaction occurs through the overlap of the respective orbitals.
Therefore, in the formation of the [CoCl4]^2- complex, the d orbitals of the cobalt atom interact with the p orbitals of the chloride ions, resulting in the formation of four sigma (σ) bonds and one pi (π) bond.
Overall, the coordination complex [CoCl4]^2- involves sp3 hybridization of the central cobalt atom's d orbitals and the overlap of these orbitals with the p orbitals of the chloride ions to form sigma (σ) and pi (π) bonds, respectively.