Suppose that D + E = A, that N/A=.25 and that D/A=.60. Solve for N/E.
Help! Explanation please. I want to understand this problem.
To solve for N/E, we need to use the given information and apply some algebraic manipulation. Let's break down the problem step by step:
1. The first equation given is D + E = A. We can rewrite this as A = D + E.
2. The second equation is N/A = 0.25. We can rearrange this equation to get N = 0.25 * A.
3. The third equation is D/A = 0.60. We can rewrite this equation to get D = 0.60 * A.
Now, let's substitute the values of A and D into the equation for N:
N = 0.25 * A
N = 0.25 * (D + E) (substituting A = D + E)
N = 0.25 * (0.60 * A + E) (substituting D = 0.60 * A)
N = 0.25 * (0.60 * A + E)
N = 0.15 * A + 0.25 * E
We want to solve for N/E, so let's rearrange the equation to isolate N/E:
N = 0.15 * A + 0.25 * E
N/E = (0.15 * A + 0.25 * E) / E
We can simplify this expression further:
N/E = (0.15 * A / E) + (0.25 * E / E)
N/E = 0.15 * (A / E) + 0.25 * 1
N/E = 0.15 * (A / E) + 0.25
Therefore, the solution for N/E is 0.15 * (A / E) + 0.25.