Balanced equation,

4KNO3(s) ----->2K2O(s) + 2N2(g) + 5O2(g)
To produce 51.8kg of O2,
How many moles of KNO3 must be heated?

How many grams of KNO3 must be heated?

Do you calculate like KNO3 and O2 is just one mole or do you divide 4/5 at the end of the equation?

51.8kgO2 x 1000g/1kg = 51800g O2 / 32.00g O2 = 1618.75g x 4/5 = 1295 moles KNO3...Is this correct?

On the right track but not quite right. You may have just mislabeled your numbers.

51,800 g O2 is what you want.
mols O2 = 51,800/32 = 1618.7 MOLES O2 (not grams) needed. Convert that to mols KNO3 by multiplying by 4/5 = 1295 mols KNO3 and you have that labeled right.

Then grams KNO3 = mols KNO3 x molar mass KNO3.

Sweet, Thank you....

What type of chemical reaction is this?



4KNO3 -> 2K2O + 2N2 + 5O2

What type of chemical reaction is this?



4KNO3 -> 2K2O + 2N2 + 5O2

To determine how many moles of KNO3 must be heated, we need to use the balanced equation.

The balanced equation is: 4KNO3(s) ➞ 2K2O(s) + 2N2(g) + 5O2(g)

From the balanced equation, we see that for every 5 moles of O2 produced, we need 4 moles of KNO3.

Given that we want to produce 51.8 kg of O2, we can convert this to grams by multiplying by 1000 g/1 kg:
51.8 kg O2 * 1000 g/1 kg = 51,800 grams of O2

Now, we use the molar mass of O2 (32.00 g/mol) to convert grams of O2 to moles of O2:
51,800 g O2 / 32.00 g/mol = 1,618.75 moles of O2

Since we know that for every 5 moles of O2 produced, we need 4 moles of KNO3, we can use this ratio to determine the moles of KNO3 required:
1,618.75 moles of O2 * (4 moles of KNO3 / 5 moles of O2) = 1,294.4 moles of KNO3

Therefore, the number of moles of KNO3 that must be heated is approximately 1,294.4 moles.

To calculate the grams of KNO3 that must be heated, you can use the molar mass of KNO3 (101.10 g/mol):
1,294.4 moles of KNO3 * 101.10 g/mol = 130,967.04 grams of KNO3

Therefore, approximately 130,967.04 grams (or 130.97 kg) of KNO3 must be heated.

Regarding your question about dividing 4/5 at the end, no, we do not divide 4/5. The ratio in the balanced equation of 4 moles of KNO3 to 5 moles of O2 is already taken into account when we use the ratio to calculate the moles of KNO3 required.