Posted by **M** on Wednesday, September 3, 2014 at 10:59pm.

Which of these equations would not be in quadratic form?

A.X^4-13X^2+36=0

B.2X^(2/5)+X^(1/5)-6=0

C.6x^3+2x^2-8X=0

D.3(2/x-4)^2+5(2/x-4)-2=0

I think its between C or D. C because the exponents are different not doubled and D because its set up is completely the opposite from all the others.

- Math -
**Steve**, Thursday, September 4, 2014 at 12:13am
It is in fact C

D is just a quadratic in (2/x-4), because if you substitute u=2/x-4, you have just 3u^2+5u-2=0

It is C because as you say, there is not

a term with twice the exponent of the other.

- Math -
**Anonymous**, Tuesday, September 30, 2014 at 8:52pm
76

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