Sunday

November 23, 2014

November 23, 2014

Posted by **M** on Wednesday, September 3, 2014 at 10:59pm.

A.X^4-13X^2+36=0

B.2X^(2/5)+X^(1/5)-6=0

C.6x^3+2x^2-8X=0

D.3(2/x-4)^2+5(2/x-4)-2=0

I think its between C or D. C because the exponents are different not doubled and D because its set up is completely the opposite from all the others.

- Math -
**Steve**, Thursday, September 4, 2014 at 12:13amIt is in fact C

D is just a quadratic in (2/x-4), because if you substitute u=2/x-4, you have just 3u^2+5u-2=0

It is C because as you say, there is not

a term with twice the exponent of the other.

- Math -
**Anonymous**, Tuesday, September 30, 2014 at 8:52pm76

**Answer this Question**

**Related Questions**

Algebra Quadratic Equations - I am trying to define the different appraoches to ...

math - can someone show me the steps for this problem because i got it incorrect...

algebra2 - Solve each of the following quadratic equations. can some explain how...

Algebra - Can you pleas Solve the quadric equation step by step 4x square =13x+...

math/algebra - subtract. express in simplest form 13x/30 - 4x/ 15 = factor the ...

math - Still looking at how to solve these... Both are cubic polynomials? 43x^3...

Math (Algebra) - A and B are real numbers such that the two quadratic equations ...

Algebra - Solve the equation using the Quadratic Formula 5xsquared+13x-6=0 i ...

advanced math - Hi, I am trying to solve graphing quadratic equations. One of ...

math - Describe the importance of quadratic equations to a basketball player, ...